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14b^2-2=-36b
We move all terms to the left:
14b^2-2-(-36b)=0
We get rid of parentheses
14b^2+36b-2=0
a = 14; b = 36; c = -2;
Δ = b2-4ac
Δ = 362-4·14·(-2)
Δ = 1408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1408}=\sqrt{64*22}=\sqrt{64}*\sqrt{22}=8\sqrt{22}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-8\sqrt{22}}{2*14}=\frac{-36-8\sqrt{22}}{28} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+8\sqrt{22}}{2*14}=\frac{-36+8\sqrt{22}}{28} $
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